-0.01x^2+16x-3900=0

Solution for -0.01x^2+16x-3900=0 equation:

-0.01x^2+16x-3900=0

a = -0.01; b = 16; c = -3900;
Δ = b2-4ac
Δ = 162-4·(-0.01)·(-3900)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-10}{2*-0.01}=\frac{-26}{-0.02}
=+1300
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+10}{2*-0.01}=\frac{-6}{-0.02}
=+300
$